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Syllabus

CH4 +4Cl2----->CCl4+4HCl

H

_{2}P_{2}O_{7}In all cases P = 5+ (max. value for oxidation state)

H is always 1+ (except in hydrides = -1)

So in this case Oxidation Number of O =

-12/7[2+10+7x = 0 so 7x = -12 therefore x = -12/7]AM I RIGHT, SIR? DID I FOLLOW THE RULES OF OXIDATION STATE/NUMBER

The equivalent mass of Cl

_{2}in the above reaction is